Mathématiques

Question

A=(x+1)^2-2(x+1) B=(2x+3)^2+(x-2)(2x+3) C=(3x-5)^2-(x+4)(3x-5)

2 Réponse

  • A = (x+1)² -2(x+1)

    A= (x+1)(x+1) -2(x+1)

    A = x² 2x +1-2x -2

    A = x² -1

     

    B= (2x+3)² +((x+2)(2x+3)

    B= 4x² +12x +9 + 2x² +3x +4x +6

    B= 6x² +19x +15

     

    C= (3x-5)² -(x+4)(3x-5)

    C= (9x² -30x +25) - ( 3x² -5x + 12x -20)

    C= 9x² -30x +25 -3x² -7x +20

    C= 6x² -37x +45

     

    Bon courage !

  • Bonjour

    A = (x+1)²-2(x+1)

    A = (x+1)(x+1)-2(x+1)

    A = (x+1)(x+1-2) 

    A =(x+1)(x-1) c'est la forme de (a+b)(a-b) = a²-b²

    A = x²-1 

    B = (2x+3)²+(x+2)(2x+3)

    B = (2x+3)(2x+3)+(x+2)(2x+3)

    B = (2x+3)(2x+3+x+2)

    B = (2x+3)(3x+5) 

    C = (3x-5)²-(x+4)(3x-5)

    C = (3x-5)(3x-5-x-4)

    C = (3x-5)(2x-9)

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